Hehe, not quite. 13461 N.
For constant acceleration a=V/t
Then F=ma
F = 2000 * 35/5.2 = 13461 N
It’s good to sense check answers. You could generate a friction force 298 N by forcing a piece of 2×4 against the ground, but you probably know that there’s no way you could stop a heavy sedan going 126 km/h in 5.2 s with that.
Anyway, what sort of idiot relates a lack of brakes to a race car? If you’re just engine braking, you’re slow.
Why spell it like breaks. Because no race car.
It’s been a while… but given the data provided, I’m guessing there need to be a resistive force of 298N?
Hehe, not quite. 13461 N.
For constant acceleration a=V/t
Then F=ma
F = 2000 * 35/5.2 = 13461 N
It’s good to sense check answers. You could generate a friction force 298 N by forcing a piece of 2×4 against the ground, but you probably know that there’s no way you could stop a heavy sedan going 126 km/h in 5.2 s with that.
Anyway, what sort of idiot relates a lack of brakes to a race car? If you’re just engine braking, you’re slow.